STCLRB, STCLRLB Atomic bit clear on byte in memory, without return This instruction atomically loads an 8-bit byte from memory, performs a bitwise AND with the complement of the value held in a register on it, and stores the result back to memory. STCLRB does not have release semantics. STCLRLB stores to memory with release semantics, as described in Load-Acquire, Store-Release. For information about addressing modes, see Load/Store addressing modes. If PSTATE.DIT is 1, the timing of this instruction is insensitive to the value of the data being loaded or stored. LDCLRB, LDCLRAB, LDCLRALB, LDCLRLB 0 0 1 1 1 0 0 0 0 1 0 0 0 1 0 0 1 1 1 1 1 0 STCLRB <Ws>, [<Xn|SP>] LDCLRB <Ws>, WZR, [<Xn|SP>] Unconditionally 1 STCLRLB <Ws>, [<Xn|SP>] LDCLRLB <Ws>, WZR, [<Xn|SP>] Unconditionally <Ws> Is the 32-bit name of the general-purpose register holding the data value to be operated on with the contents of the memory location, encoded in the "Rs" field. <Xn|SP> Is the 64-bit name of the general-purpose base register or stack pointer, encoded in the "Rn" field.