# What `#[derive(MulAssign)]` generates This code is very similar to the code that is generated for `#[derive(Mul)]`. The difference is that it mutates the existing instance instead of creating a new one. You can add the `#[mul_assign(forward)]` attribute if you don't want the same semantics as `Mul`. This will instead generate a `MulAssign` implementation with the same semantics as `AddAssign`. ## Tuple structs When deriving `MulAssign` for a tuple struct with two fields like this: ```rust # use derive_more::MulAssign; # #[derive(MulAssign)] struct MyInts(i32, i32); ``` Code like this will be generated: ```rust # struct MyInts(i32, i32); impl<__RhsT: Copy> derive_more::MulAssign<__RhsT> for MyInts where i32: derive_more::MulAssign<__RhsT> { fn mul_assign(&mut self, rhs: __RhsT) { self.0.mul_assign(rhs); self.1.mul_assign(rhs); } } ``` The behaviour is similar with more or less fields, except for the fact that `__RhsT` does not need to implement `Copy` when only a single field is present. ## Regular structs When deriving `MulAssign` for a regular struct with two fields like this: ```rust # use derive_more::MulAssign; # #[derive(MulAssign)] struct Point2D { x: i32, y: i32, } ``` Code like this will be generated: ```rust # struct Point2D { # x: i32, # y: i32, # } impl<__RhsT: Copy> derive_more::MulAssign<__RhsT> for Point2D where i32: derive_more::MulAssign<__RhsT> { fn mul_assign(&mut self, rhs: __RhsT) { self.x.mul_assign(rhs); self.y.mul_assign(rhs); } } ``` The behaviour is again similar with more or less fields, except that `Copy` doesn't have to be implemented for `__Rhst` when the struct has only a single field. ## Enums Deriving `MulAssign` for enums is not (yet) supported. This has two reason, the first being that deriving `Mul` is also not implemented for enums yet. The second reason is the same as for `AddAssign`. Even if it would be deriving `Mul` was implemented it would likely return a `Result` instead of an `EnumType`. Handling the case where it errors would be hard and maybe impossible.