/*========================================================================= Program: GDCM (Grassroots DICOM). A DICOM library Copyright (c) 2006-2011 Mathieu Malaterre All rights reserved. See Copyright.txt or http://gdcm.sourceforge.net/Copyright.html for details. This software is distributed WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the above copyright notice for more information. =========================================================================*/ /* * WARNING: This is a dev tool, do not use ! * * Usage: after a gdcmconv, you would like to know if the conversion process is acceptable * sometime a vbindiff is acceptable, sometime it is not. In the case of the famous Philips * Little/Big Endian Explicit Transfer Syntax it is not easy to compare two files. However * this only impact byte ordering, thus we can compute byte-indenpendant information to still * compare the files. */ #include "gdcmImageReader.h" #include "gdcmImage.h" #include "gdcmWriter.h" #include "gdcmAttribute.h" #include "gdcmSystem.h" #include #include int main(int argc, char *argv[]) { if( argc < 3 ) { std::cerr << argv[0] << " input1.dcm input2.dcm" << std::endl; return 1; } const char *filename1 = argv[1]; const char *filename2 = argv[2]; gdcm::ImageReader reader1; reader1.SetFileName( filename1 ); if( !reader1.Read() ) { std::cerr << "Could not read: " << filename1 << std::endl; return 1; } gdcm::ImageReader reader2; reader2.SetFileName( filename2 ); if( !reader2.Read() ) { std::cerr << "Could not read: " << filename2 << std::endl; return 1; } // TODO: need a DataSet== operator implementation std::cout << "Both files can be read and looks like DICOM" << std::endl; size_t s1 = gdcm::System::FileSize(filename1); size_t s2 = gdcm::System::FileSize(filename2); if( s1 != s2 ) { std::cout << "Size mismatch: " << s1 << " != " << s2 << std::endl; return 1; } else { std::cout << "Size match: " << s1 << " = " << s2 << std::endl; } std::ifstream is1( filename1, std::ios::binary ); char *buffer1 = new char[s1]; is1.read(buffer1, s1); std::ifstream is2( filename2, std::ios::binary ); char *buffer2 = new char[s2]; is2.read(buffer2, s2); assert( s1 == s2 ); if( memcmp(buffer1, buffer2, s1 ) == 0 ) { std::cout << "memcmp succeed ! File are bit identical" << std::endl; } else { std::cout << "memcmp failed!" << std::endl; } // Hum...memcmp failed, for big endian/ little endian inversion the histogram of bytes // should still be the same. So let's compute it // buffer2[0] = 1; // let's make the test fail std::multiset set1( buffer1, buffer1 + s1 ); std::multiset set2( buffer2, buffer2 + s2 ); if( set1 == set2 ) { std::cout << "set1 == set2. Byte histogram seems valid" << std::endl; } else { std::cout << "set1 != set2" << std::endl; } delete[] buffer1; delete[] buffer2; return 0; }