/*========================================================================= Program: GDCM (Grassroots DICOM). A DICOM library Copyright (c) 2006-2011 Mathieu Malaterre All rights reserved. See Copyright.txt or http://gdcm.sourceforge.net/Copyright.html for details. This software is distributed WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the above copyright notice for more information. =========================================================================*/ #include "gdcmDicts.h" #include "gdcmGlobal.h" #include "gdcmDict.h" #include int TestDicts(int, char *[]) { gdcm::Dicts dicts; //const gdcm::Dict &d = dicts.GetPublicDict(); //std::cout << d << std::endl; const gdcm::Global& g = gdcm::GlobalInstance; // get the Part 6 dicts from it: const gdcm::Dicts &ds = g.GetDicts(); const gdcm::Dict &pub = ds.GetPublicDict(); gdcm::Dict::ConstIterator it = pub.Begin(); int ret = 0; std::set names; for( ; it != pub.End(); ++it) { const gdcm::Tag &t = it->first; const gdcm::DictEntry &de = it->second; // A couple of tests: if( t.GetElement() == 0x0 ) { // Check group length if( de.GetVR() != gdcm::VR::UL || de.GetVM() != gdcm::VM::VM1 ) { std::cerr << "Group length issue: Problem with tag: " << t << " " << de << std::endl; ++ret; } } // I need a test that check there is no duplicate name for data elements since python-gdcm // will rely on it if( names.count( de.GetName() ) != 0 ) { //std::cerr << "Name issue: Problem with tag: " << t << " " << de << std::endl; //++ret; } names.insert( de.GetName() ); } return ret; }