/*
 * @lc app=leetcode id=1111 lang=rust
 *
 * [1111] Maximum Nesting Depth of Two Valid Parentheses Strings
 *
 * https://leetcode.com/problems/maximum-nesting-depth-of-two-valid-parentheses-strings/description/
 *
 * algorithms
 * Medium (68.97%)
 * Total Accepted:    6.6K
 * Total Submissions: 9.5K
 * Testcase Example:  '"(()())"'
 *
 * A string is a valid parentheses string (denoted VPS) if and only if it
 * consists of "(" and ")" characters only, and:
 * 
 * 
 * It is the empty string, or
 * It can be written as AB (A concatenated with B), where A and B are VPS's,
 * or
 * It can be written as (A), where A is a VPS.
 * 
 * 
 * We can similarly define the nesting depth depth(S) of any VPS S as
 * follows:
 * 
 * 
 * depth("") = 0
 * depth(A + B) = max(depth(A), depth(B)), where A and B are VPS's
 * depth("(" + A + ")") = 1 + depth(A), where A is a VPS.
 * 
 * 
 * For example,  "", "()()", and "()(()())" are VPS's (with nesting depths 0,
 * 1, and 2), and ")(" and "(()" are not VPS's.
 * 
 * 
 * 
 * Given a VPS seq, split it into two disjoint subsequences A and B, such that
 * A and B are VPS's (and A.length + B.length = seq.length).
 * 
 * Now choose any such A and B such that max(depth(A), depth(B)) is the minimum
 * possible value.
 * 
 * Return an answer array (of length seq.length) that encodes such a choice of
 * A and B:  answer[i] = 0 if seq[i] is part of A, else answer[i] = 1.  Note
 * that even though multiple answers may exist, you may return any of them.
 * 
 * 
 * Example 1:
 * 
 * 
 * Input: seq = "(()())"
 * Output: [0,1,1,1,1,0]
 * 
 * 
 * Example 2:
 * 
 * 
 * Input: seq = "()(())()"
 * Output: [0,0,0,1,1,0,1,1]
 * 
 * 
 * 
 * Constraints:
 * 
 * 
 * 1 <= seq.size <= 10000
 * 
 * 
 */
impl Solution {
    pub fn max_depth_after_split(seq: String) -> Vec<i32> {
        let mut res = vec![0]; 
        let cs:Vec<char> = seq.chars().collect();
        for i in 1..seq.len() {
            res.push(if cs[i] == '(' { i as i32 & 1 } else { 1 - (i as i32 & 1)});
        }
        res 
    }
}

// pub structSolution; 
use std::collections::HashMap;
use std::collections::HashSet;
use std::fmt::Debug;
use std::hash::Hash;
use std::iter::FromIterator;
use std::collections::VecDeque; 

#[allow(dead_code)]
pub fn print_map<K: Debug + Eq + Hash, V: Debug>(map: &HashMap<K, V>) {
    for (k, v) in map.iter() {
        println!("{:?}: {:?}", k, v);
    }
}

#[allow(dead_code)]
pub fn say_vec(nums: Vec<i32>){
	println!("{:?}", nums);
}

#[allow(dead_code)]
pub fn char_frequency(s: String) -> HashMap<char, i32> {
    let mut res:HashMap<char, i32> = HashMap::new(); 
    for c in s.chars(){
        *res.entry(c).or_insert(0) += 1;
    }
    res 
}

#[allow(dead_code)]
pub fn vec_counter(arr: Vec<i32>) -> HashMap<i32, i32> {
    let mut c = HashMap::new(); 
    for n in arr { *c.entry(n).or_insert(0) += 1; }
    c 
}

#[allow(dead_code)]
pub fn vec_to_hashset(arr: Vec<i32>) -> HashSet<i32> {
   HashSet::from_iter(arr.iter().cloned())
}