/*
 * @lc app=leetcode id=832 lang=rust
 *
 * [832] Flipping an Image
 *
 * https://leetcode.com/problems/flipping-an-image/description/
 *
 * algorithms
 * Easy (74.71%)
 * Total Accepted:    147.8K
 * Total Submissions: 197.8K
 * Testcase Example:  '[[1,1,0],[1,0,1],[0,0,0]]'
 *
 * Given a binary matrix A, we want to flip the image horizontally, then invert
 * it, and return the resulting image.
 * 
 * To flip an image horizontally means that each row of the image is reversed.
 * For example, flipping [1, 1, 0] horizontally results in [0, 1, 1].
 * 
 * To invert an image means that each 0 is replaced by 1, and each 1 is
 * replaced by 0. For example, inverting [0, 1, 1] results in [1, 0, 0].
 * 
 * Example 1:
 * 
 * 
 * Input: [[1,1,0],[1,0,1],[0,0,0]]
 * Output: [[1,0,0],[0,1,0],[1,1,1]]
 * Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
 * Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
 * 
 * 
 * Example 2:
 * 
 * 
 * Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
 * Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
 * Explanation: First reverse each row:
 * [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
 * Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
 * 
 * 
 * Notes:
 * 
 * 
 * 1 <= A.length = A[0].length <= 20
 * 0 <= A[i][j] <= 1
 * 
 * 
 */
impl Solution {
    pub fn flip_and_invert_image(a: Vec<Vec<i32>>) -> Vec<Vec<i32>> {
        a.iter().map(|row| row.iter().rev().map(|n| 1 - n).collect()).collect()
    }
}
// pub structSolution;