const aVeryLongNameThatGoesOnAndOn = this.someOtherObject.someOtherNestedObject.someLongFunctionName();

this.someObject.someOtherNestedObject = this.someOtherObject.whyNotNestAnotherOne.someLongFunctionName();

this.isaverylongmethodexpression.withmultiplelevels = this.isanotherverylongexpression.thatisalsoassigned = 0;