#!/usr/bin/env python3 # Copyright (c) 2014-2016 The Bitcoin Core developers # Distributed under the MIT software license, see the accompanying # file COPYING or http://www.opensource.org/licenses/mit-license.php. """Test descendant package tracking code.""" from decimal import Decimal from test_framework.messages import COIN from test_framework.test_framework import BitcoinTestFramework from test_framework.util import ( assert_equal, assert_raises_rpc_error, satoshi_round, sync_blocks, sync_mempools, ) MAX_ANCESTORS = 25 MAX_DESCENDANTS = 25 class MempoolPackagesTest(BitcoinTestFramework): def set_test_params(self): self.num_nodes = 2 self.extra_args = [["-maxorphantx=1000"], ["-maxorphantx=1000", "-limitancestorcount=5"]] # Build a transaction that spends parent_txid:vout # Return amount sent def chain_transaction(self, node, parent_txid, vout, value, fee, num_outputs): send_value = satoshi_round((value - fee) / num_outputs) inputs = [{'txid': parent_txid, 'vout': vout}] outputs = {} for i in range(num_outputs): outputs[node.getnewaddress()] = send_value rawtx = node.createrawtransaction(inputs, outputs) signedtx = node.signrawtransactionwithwallet(rawtx) txid = node.sendrawtransaction(signedtx['hex']) fulltx = node.getrawtransaction(txid, 1) # make sure we didn't generate a change output assert(len(fulltx['vout']) == num_outputs) return (txid, send_value) def run_test(self): ''' Mine some blocks and have them mature. ''' self.nodes[0].generate(101) utxo = self.nodes[0].listunspent(10) txid = utxo[0]['txid'] vout = utxo[0]['vout'] value = utxo[0]['amount'] fee = Decimal("0.0001") # MAX_ANCESTORS transactions off a confirmed tx should be fine chain = [] for i in range(MAX_ANCESTORS): (txid, sent_value) = self.chain_transaction( self.nodes[0], txid, 0, value, fee, 1) value = sent_value chain.append(txid) # Check mempool has MAX_ANCESTORS transactions in it, and descendant and ancestor # count and fees should look correct mempool = self.nodes[0].getrawmempool(True) assert_equal(len(mempool), MAX_ANCESTORS) descendant_count = 1 descendant_fees = 0 descendant_size = 0 ancestor_size = sum([mempool[tx]['size'] for tx in mempool]) ancestor_count = MAX_ANCESTORS ancestor_fees = sum([mempool[tx]['fee'] for tx in mempool]) descendants = [] ancestors = list(chain) for x in reversed(chain): # Check that getmempoolentry is consistent with getrawmempool entry = self.nodes[0].getmempoolentry(x) assert_equal(entry, mempool[x]) # Check that the descendant calculations are correct assert_equal(mempool[x]['descendantcount'], descendant_count) descendant_fees += mempool[x]['fee'] assert_equal(mempool[x]['modifiedfee'], mempool[x]['fee']) assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN) descendant_size += mempool[x]['size'] assert_equal(mempool[x]['descendantsize'], descendant_size) descendant_count += 1 # Check that ancestor calculations are correct assert_equal(mempool[x]['ancestorcount'], ancestor_count) assert_equal(mempool[x]['ancestorfees'], ancestor_fees * COIN) assert_equal(mempool[x]['ancestorsize'], ancestor_size) ancestor_size -= mempool[x]['size'] ancestor_fees -= mempool[x]['fee'] ancestor_count -= 1 # Check that parent/child list is correct assert_equal(mempool[x]['spentby'], descendants[-1:]) assert_equal(mempool[x]['depends'], ancestors[-2:-1]) # Check that getmempooldescendants is correct assert_equal(sorted(descendants), sorted( self.nodes[0].getmempooldescendants(x))) # Check getmempooldescendants verbose output is correct for descendant, dinfo in self.nodes[0].getmempooldescendants(x, True).items(): assert_equal(dinfo['depends'], [ chain[chain.index(descendant) - 1]]) if dinfo['descendantcount'] > 1: assert_equal(dinfo['spentby'], [ chain[chain.index(descendant) + 1]]) else: assert_equal(dinfo['spentby'], []) descendants.append(x) # Check that getmempoolancestors is correct ancestors.remove(x) assert_equal(sorted(ancestors), sorted( self.nodes[0].getmempoolancestors(x))) # Check that getmempoolancestors verbose output is correct for ancestor, ainfo in self.nodes[0].getmempoolancestors(x, True).items(): assert_equal(ainfo['spentby'], [ chain[chain.index(ancestor) + 1]]) if ainfo['ancestorcount'] > 1: assert_equal(ainfo['depends'], [ chain[chain.index(ancestor) - 1]]) else: assert_equal(ainfo['depends'], []) # Check that getmempoolancestors/getmempooldescendants correctly handle verbose=true v_ancestors = self.nodes[0].getmempoolancestors(chain[-1], True) assert_equal(len(v_ancestors), len(chain) - 1) for x in v_ancestors.keys(): assert_equal(mempool[x], v_ancestors[x]) assert(chain[-1] not in v_ancestors.keys()) v_descendants = self.nodes[0].getmempooldescendants(chain[0], True) assert_equal(len(v_descendants), len(chain) - 1) for x in v_descendants.keys(): assert_equal(mempool[x], v_descendants[x]) assert(chain[0] not in v_descendants.keys()) # Check that ancestor modified fees includes fee deltas from # prioritisetransaction self.nodes[0].prioritisetransaction(chain[0], 0, 1000) mempool = self.nodes[0].getrawmempool(True) ancestor_fees = 0 for x in chain: ancestor_fees += mempool[x]['fee'] assert_equal(mempool[x]['ancestorfees'], ancestor_fees * COIN + 1000) # Undo the prioritisetransaction for later tests self.nodes[0].prioritisetransaction(chain[0], 0, -1000) # Check that descendant modified fees includes fee deltas from # prioritisetransaction self.nodes[0].prioritisetransaction(chain[-1], 0, 1000) mempool = self.nodes[0].getrawmempool(True) descendant_fees = 0 for x in reversed(chain): descendant_fees += mempool[x]['fee'] assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN + 1000) # Adding one more transaction on to the chain should fail. assert_raises_rpc_error(-26, "too-long-mempool-chain", self.chain_transaction, self.nodes[0], txid, vout, value, fee, 1) # Check that prioritising a tx before it's added to the mempool works # First clear the mempool by mining a block. self.nodes[0].generate(1) sync_blocks(self.nodes) assert_equal(len(self.nodes[0].getrawmempool()), 0) # Prioritise a transaction that has been mined, then add it back to the # mempool by using invalidateblock. self.nodes[0].prioritisetransaction(chain[-1], 0, 2000) self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash()) # Keep node1's tip synced with node0 self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash()) # Now check that the transaction is in the mempool, with the right modified fee mempool = self.nodes[0].getrawmempool(True) descendant_fees = 0 for x in reversed(chain): descendant_fees += mempool[x]['fee'] if (x == chain[-1]): assert_equal(mempool[x]['modifiedfee'], mempool[x]['fee'] + satoshi_round(0.00002)) assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN + 2000) # TODO: check that node1's mempool is as expected # TODO: test ancestor size limits # Now test descendant chain limits txid = utxo[1]['txid'] value = utxo[1]['amount'] vout = utxo[1]['vout'] transaction_package = [] tx_children = [] # First create one parent tx with 10 children (txid, sent_value) = self.chain_transaction( self.nodes[0], txid, vout, value, fee, 10) parent_transaction = txid for i in range(10): transaction_package.append( {'txid': txid, 'vout': i, 'amount': sent_value}) # Sign and send up to MAX_DESCENDANT transactions chained off the parent tx for i in range(MAX_DESCENDANTS - 1): utxo = transaction_package.pop(0) (txid, sent_value) = self.chain_transaction( self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10) if utxo['txid'] is parent_transaction: tx_children.append(txid) for j in range(10): transaction_package.append( {'txid': txid, 'vout': j, 'amount': sent_value}) mempool = self.nodes[0].getrawmempool(True) assert_equal(mempool[parent_transaction] ['descendantcount'], MAX_DESCENDANTS) assert_equal(sorted(mempool[parent_transaction] ['spentby']), sorted(tx_children)) for child in tx_children: assert_equal(mempool[child]['depends'], [parent_transaction]) # Sending one more chained transaction will fail utxo = transaction_package.pop(0) assert_raises_rpc_error(-26, "too-long-mempool-chain", self.chain_transaction, self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10) # TODO: check that node1's mempool is as expected # TODO: test descendant size limits # Test reorg handling # First, the basics: self.nodes[0].generate(1) sync_blocks(self.nodes) self.nodes[1].invalidateblock(self.nodes[0].getbestblockhash()) self.nodes[1].reconsiderblock(self.nodes[0].getbestblockhash()) # Now test the case where node1 has a transaction T in its mempool that # depends on transactions A and B which are in a mined block, and the # block containing A and B is disconnected, AND B is not accepted back # into node1's mempool because its ancestor count is too high. # Create 8 transactions, like so: # Tx0 -> Tx1 (vout0) # \--> Tx2 (vout1) -> Tx3 -> Tx4 -> Tx5 -> Tx6 -> Tx7 # # Mine them in the next block, then generate a new tx8 that spends # Tx1 and Tx7, and add to node1's mempool, then disconnect the # last block. # Create tx0 with 2 outputs utxo = self.nodes[0].listunspent() txid = utxo[0]['txid'] value = utxo[0]['amount'] vout = utxo[0]['vout'] send_value = satoshi_round((value - fee) / 2) inputs = [{'txid': txid, 'vout': vout}] outputs = {} for i in range(2): outputs[self.nodes[0].getnewaddress()] = send_value rawtx = self.nodes[0].createrawtransaction(inputs, outputs) signedtx = self.nodes[0].signrawtransactionwithwallet(rawtx) txid = self.nodes[0].sendrawtransaction(signedtx['hex']) tx0_id = txid value = send_value # Create tx1 tx1_id, _ = self.chain_transaction( self.nodes[0], tx0_id, 0, value, fee, 1) # Create tx2-7 vout = 1 txid = tx0_id for i in range(6): (txid, sent_value) = self.chain_transaction( self.nodes[0], txid, vout, value, fee, 1) vout = 0 value = sent_value # Mine these in a block self.nodes[0].generate(1) self.sync_all() # Now generate tx8, with a big fee inputs = [{'txid': tx1_id, 'vout': 0}, {'txid': txid, 'vout': 0}] outputs = {self.nodes[0].getnewaddress(): send_value + value - 4 * fee} rawtx = self.nodes[0].createrawtransaction(inputs, outputs) signedtx = self.nodes[0].signrawtransactionwithwallet(rawtx) txid = self.nodes[0].sendrawtransaction(signedtx['hex']) sync_mempools(self.nodes) # Now try to disconnect the tip on each node... self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash()) self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash()) sync_blocks(self.nodes) if __name__ == '__main__': MempoolPackagesTest().main()