# Problem 419: Look and say sequence
The look and say sequence goes 1, 11, 21, 1211, 111221, 312211,
13112221, 1113213211, ... The sequence starts with 1 and all other
members are obtained by describing the previous member in terms of
consecutive digits. It helps to do this out loud: 1 is 'one one' → 11 11
is 'two ones' → 21 21 is 'one two and one one' → 1211 1211 is 'one one,
one two and two ones' → 111221 111221 is 'three ones, two twos and one
one' → 312211 ... Define A(n), B(n) and C(n) as the number of ones, twos
and threes in the n'th element of the sequence respectively. One can
verify that A(40) = 31254, B(40) = 20259 and C(40) = 11625. Find A(n),
B(n) and C(n) for n = 1012. Give your answer modulo 230 and separate
your values for A, B and C by a comma. E.g. for n = 40 the answer would
be 31254,20259,11625