# Problem 526: Largest prime factors of consecutive numbers

![graphic](img526.gif)

Let f(n) be the largest prime factor of n. Let g(n) = f(n) + f(n+1) +
f(n+2) + f(n+3) + f(n+4) + f(n+5) + f(n+6) + f(n+7) + f(n+8), the sum of
the largest prime factor of each of nine consecutive numbers starting
with n. Let h(n) be the maximum value of g(k) for 2 ≤ k ≤ n. You are
given: f(100) = 5 f(101) = 101 g(100) = 409 h(100) = 417 h(109) =
4896292593Find h(1016).