Crates.io | sparsevec |
lib.rs | sparsevec |
version | 0.2.0 |
source | src |
created_at | 2018-10-17 09:12:48.440711 |
updated_at | 2022-07-25 15:46:26.481702 |
description | Compress vectors using row displacement |
homepage | |
repository | https://github.com/softdevteam/sparsevec/ |
max_upload_size | |
id | 91121 |
size | 18,907 |
A SparseVec efficiently encodes a two-dimensional matrix of integers. The input matrix must be encoded as a one-dimensional vector of integers with a row-length. Given an empty value, the SparseVec uses row displacement as described in [1] for the compression and encodes the result further using a PackedVec.
[1] Tarjan, Robert Endre, and Andrew Chi-Chih Yao. "Storing a sparse table." Communications of the ACM 22.11 (1979): 606-611.
extern crate sparsevec;
use sparsevec::SparseVec;
fn main() {
use sparsevec::SparseVec;
let v:Vec<usize> = vec![1,0,0,0,
0,0,7,8,
9,0,0,3];
let sv = SparseVec::from(&v, 0, 4);
assert_eq!(sv.get(0,0).unwrap(), 1);
assert_eq!(sv.get(1,2).unwrap(), 7);
assert_eq!(sv.get(2,3).unwrap(), 3);
}
The following describes the general idea of row displacement for sparse vectors, excluding some additional optimisations from the implementation. Let's take as an example the two-dimensional vector
1 0 0
2 0 0
3 0 0
0 0 4
represented as a one dimensional vector v = [1,0,0,2,0,0,3,0,0,0,0,4]
with row-length 3.
Storing this vector in memory is wasteful as the majority of its elements is 0. We can compress
this vector using row displacement, which merges all rows into a vector such that no two
non-zero entries are mapped to the same position. For the above example, this would result in
the compressed vector c = [1,2,3,0,4]
:
1 0 0
2 0 0
3 0 0
0 0 4
---------
1 2 3 0 4
To retrieve values from the compressed vector, we need a displacement vector, which
describes how much each row was shifted during the compression. For the above example, the
displacement vector would be d = [0, 1, 2, 2]
. In order to retrieve the value at
position (2, 0), we can calculate its compressed position with pos = d[row] + col
:
pos = d[2] + 0 // =2
value = c[pos] // =3